x-5y^2+40y-80=0

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Solution for x-5y^2+40y-80=0 equation:


Simplifying
x + -5y2 + 40y + -80 = 0

Reorder the terms:
-80 + x + 40y + -5y2 = 0

Solving
-80 + x + 40y + -5y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '80' to each side of the equation.
-80 + x + 40y + 80 + -5y2 = 0 + 80

Reorder the terms:
-80 + 80 + x + 40y + -5y2 = 0 + 80

Combine like terms: -80 + 80 = 0
0 + x + 40y + -5y2 = 0 + 80
x + 40y + -5y2 = 0 + 80

Combine like terms: 0 + 80 = 80
x + 40y + -5y2 = 80

Add '-40y' to each side of the equation.
x + 40y + -40y + -5y2 = 80 + -40y

Combine like terms: 40y + -40y = 0
x + 0 + -5y2 = 80 + -40y
x + -5y2 = 80 + -40y

Add '5y2' to each side of the equation.
x + -5y2 + 5y2 = 80 + -40y + 5y2

Combine like terms: -5y2 + 5y2 = 0
x + 0 = 80 + -40y + 5y2
x = 80 + -40y + 5y2

Simplifying
x = 80 + -40y + 5y2

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